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x^2/6=36+x/6
We move all terms to the left:
x^2/6-(36+x/6)=0
We add all the numbers together, and all the variables
x^2/6-(x/6+36)=0
We get rid of parentheses
x^2/6-x/6-36=0
We multiply all the terms by the denominator
x^2-x-36*6=0
We add all the numbers together, and all the variables
x^2-1x-216=0
a = 1; b = -1; c = -216;
Δ = b2-4ac
Δ = -12-4·1·(-216)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{865}}{2*1}=\frac{1-\sqrt{865}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{865}}{2*1}=\frac{1+\sqrt{865}}{2} $
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